Question

ayuda, es para ahora!!

Answer 1

Respuesta:

Los dos valores posibles de x que dan respuesta al planteamiento son:

x₁ = 2

x₂ = 5.333

Explicación paso a paso:

{(x-2)²/2} - {(5(x+1))/3} = -5

{(x²-4x+4)/2} - {(5x+5)/3} = -5

{3(x²-4x+4)/(3*2)} - {2{5x+5)/(2*3)} = -5

{(3x²-12x+12)/6} - {(10x+10)/6} = -5

{3x²-12x+12-10x-10} / 6 = -5

{3x² -22x + 2} / 6 = -5

3x²-22x + 2 = -5*6

3x²-22x+2 = -30

3x²-22x+2+30 = 0

3x²-22x+32 = 0

x = {22±√(-22²-(4*3*32))} / (2*3)

x = {22±√(484-384)} / 6

x = {22±√100} / 6

x = {22±10} / 6

x₁ = {22-10} / 6 = 12/6 = 2

x₂ = {22+10} / 6 = 32/6 = 5.333

Comprobación:

x₁

(2-2)²/2  - 5(2+1)/3 = -5

-5*3/3 = -5

x₂

{(5.333-2)²/2} - {(5*(5.333+1)/3} = -5

3.333²/2 - 5*6.333/3 = -5

11.11/2 -  31.6665/3 = -5

5.555 - 10.555 = -5