Question

(x-2)^2+x(x-3)=3(x+4)(x-3)(x+2)(x-1)+2

Answer 1

(x-2)^2+x(x-3)=3(x+4)(x-3)(x+2)(x-1)+2x²-4x+4 + x²-6x = 3(x²-3x+4x-12)(x²-x+2x-2)+2
2x²-10x+4 = 3(x²+x-12)(x²+x-2)+2
2x²-10x+4 = 3x²+3x-36(x²+x-2) + 2
2x²-10x+4 = 3x^4 + 3x³ - 6x² + 3x³ + 3x² -6x -36x² - 36x + 72 +2
2x²-10x+4 = 3x^4 + 6x³ - 39x² - 42x + 74
3x^4 - 6x³ + 41x² + 32x = 70 ... 
 

Answer 2

Respuesta:

×12+311+61=6+52/+77+_1_+6/+/+51+7113syqg1

Explicación paso a paso: