Question

ayuda por favor, no entiendo bien estas operaciones.​

Answer 1

Explicación paso a paso:

Tengamos primero claro que:

 sen(30) = 1/2

 cos(30) = √3/2

 tan(30) = √3/3

 sec(30)=1/cos(30)= 2√3/3

 

 sen(45) = √2/2

 cos(45) = √2/2

 tan(45) = 1

 sec(45) = 1/cos(45) = √2

 sen(60) = √3/2

 cos(60)= 1/2

 tan(60) = √3

Luego:

A) 1/cos(30)+1/tan(60)-1/sen(45) = 1/(√3/2)+1/(√3)-1/(√2/2) = √3-√2

B) (sen(60)-cos²(45))/cos(60) = (1/2-(√2/2)²)/(1/2) = 0

C) (2sen(30)*cos(30))/(cos(60)+sec(30)) = (2*1/2*√3/2)/(1/2+2√3/3) ≈ 0,52

D) (sen²(30)+cos²(30)+1)/(sec(45)*tan(30)) = ((1/2)²+(√3/2)²+1)/(√2*√3/3) = √6

Answer 2

Explicación paso a paso:sen(30) = 1/2

 cos(30) = √3/2

 tan(30) = √3/3

 sec(30)=1/cos(30)= 2√3/3

 

 sen(45) = √2/2

 cos(45) = √2/2

 tan(45) = 1

 sec(45) = 1/cos(45) = √2

 sen(60) = √3/2

 cos(60)= 1/2

 tan(60) = √3

Luego:

A) 1/cos(30)+1/tan(60)-1/sen(45) = 1/(√3/2)+1/(√3)-1/(√2/2) = √3-√2

B) (sen(60)-cos²(45))/cos(60) = (1/2-(√2/2)²)/(1/2) = 0

C) (2sen(30)*cos(30))/(cos(60)+sec(30)) = (2*1/2*√3/2)/(1/2+2√3/3) ≈ 0,52

D) (sen²(30)+cos²(30)+1)/(sec(45)*tan(30)) = ((1/2)²+(√3/2)²+1)/(√2*√3/3) = √6