Question

Log(x-8)+log(x-2)=log7

Answer 1

${10}^{ log(x - 8) } + {10}^{ log(x - 2) } = {10}^{ log(7) } \\ se \: simplifica \: los \: logaritmos \\ (x - 8) + (x - 2) = 7 \\ x - 8 + x - 2 = 7 \\ 2x - 10 = 7 \\ 2x = 7 + 10 \\ 2x = 17 \\ x = \frac{17}{2} = 8.5$