Question

Resolver la ecuacion de orden superior x^3+4x^2+x-6=0

Answer 1

factorizar$x^{3} +4x^{2} +x-6: (x-1)(x+2)(x+3)$

$(x-1)(x+2)(x+3)=0$

resolver

$x-1=0:   x=1$

resolver

$x+2=0:   x=-2$

resolver

$x+3=0:   x=-3$

solucion final

x =1      x= -2      x= -3