Question

Resolver simplificando: LaTeX: \frac{2x-3}{x+5}.\frac{x^2-25}{6x-9}

Answer 1

PREGUNTA

Resolver simplificando:  $\frac{2x-3}{x+5} \times \frac{x^2-25}{6x-9}$

SOLUCIÓN

Hola!! :D

Recuerda que

                    $\boxed{\boxed{\boldsymbol{a^{2} -b^{2} = (a+b)(a-b)}}}$

Entonces

                           $\dfrac{2x-3}{x+5} \times \dfrac{x^2-25}{6x-9}\\\\\\\dfrac{2x-3}{x+5} \times \dfrac{(x+5)(x-5)}{3(2x-3)}\\\\Simplificamos \\\\\dfrac{1}{x+5} \times \dfrac{(x-5)}{3}\\\\\\\boxed{\boxed{\boldsymbol{\dfrac{x-5}{3(x+5)}}}}}$

Answer 2

[(2x-3)/(x+5)][(x²-25)/(6x-9)] =(x-5)/3

Explicación paso a paso:

Resolver:

[(2x-3)/(x+5)][(x²-25)/(6x-9)] =

Factorizamos:

Recordemos que  (a+b)(a-b) = a²-b² (Producto noble llamado cuadrado de un binomio)

[(2x-3)/(x+5)][(x+5)(x-5)/3(2x-3)] =

Eliminamos las expresiones comunes entre numerador y denominador:

[1/1][(x-5)/3] =(x-5)/3

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