Question

Resolver la ecuación cudratica de la forma ax^{2} + bx + c = 0

\frac{1}{x+5} - \frac{1}{x-5} = 1

Answer 1

(1/(x+5))-(1/(x-5))=1

(x-5)-(x+5)=(x-5)(x+5)

-10=x^2-25

0=x^2-15

x^2=25

$\times 1 = \sqrt{15}$

$\times 2 = - \sqrt{15}$