Question

Ayuda 25 ejercicios de binomios a trinomios resueltos porfa

Answer 1

Respuesta:

X+1)2 = X2 + 2X + 1

(X-1)2 = X2 – 2X + 1

(3+6)2 = 81

(4B+3C)2 = 16B2 + 24BC+ 9C2

(56-36)2 = 400

(3/5 A + ½ B)2 = 9/25 A2 + ¼ B2

(2*A2 + 5* B2)2 = 4A4 + 25B 4

(10000-1000)2 = 90002

(2A – 3B)2 = 4A2 – 12AB + 9B2

(5ABC-5BCD)2 = 25A2 – 25D2

(999-666)2 = 3332

(A-6)2 = A2 – 12A +36

(8a2b + 7ab6y²)² = 64a4b² + 112a3b7y² + 49a²b12y4  

(A3+4B2)2 = A6 + 8A3B2 +16A4

(1,5xy² + 2,5xy)² = 2.25 x²y4+ 7,5x³y³ + 6,25x4y²  

(3x – 4)2 = 9x2 – 24x – 16

(x – 5)2 =x2 -10x+ 25

-(x – 3)2 = -x2+ 6x-9

(3x5 + 8)2 = 9x10 + 48x5 + 64

Explicación paso a paso:

Answer 2

Respuesta: BINOMIO

Explicación paso a paso:

1. (2 + x)² = 2² + 2(2)(x) + x²

= 4 + 4x + x²

2. (3a – 5b)² = (3a)² - 2(3a)(5b) + (5b)²

= 9a² - 30ab + 25b²

5. (x + y)² = x² + 2 (x)(y) + y²

= x² + 2xy + y²

6. (p - q)² = p² - 2pq + q²

7. (2p + q)² = (2p)² + 2(2p)(q) + q²

= 4p² + 4pq + q² 

8. (3a + b)² = (3a)² + 2(3a)(b) + b²

= 9a² + 6ab + b²

9. (2a - 3b)² = (2a)² - 2(2a)(3b) + (3b)²

= 4a² - 12ab + 9b²

10. (x + 1)² = x² + 2(x)(1) + (1)²

= x² + 2x + 1

11. (a - 6)² = (a)² - 2(a)(6) + (6)²

= a² - 12a + 36

12. (x + 9)² = (x)² + 2(x)(9) + (9)²

= x² + 18x + 81

13. (3p - 1)² = (3p)² - 2(3p)(1) + (1)²

= 9p² - 6p + 1 

14. (x + 5)² = (x)² + 2(x)(5) + (5)²

= x² + 10x + 25 

15. (6x – 5y)² = (6x)² - 2(6x)(5y) + (5y)²

= 36x² - 60xy + 25y²

16.- (2m – 1)² = (2m)² - 2(2m)(1) + (1)²

= 4m² - 4m + 1 

17. (4pq - 3q)² = (4pq)² - 2(4pq)(3q) + (3q)²

= 16 p² q² – 24pq² + 9q²

18. (9x2 – 7y2)² = (9x²)² - 2(9x²)(7y²) + (7y²)²

= 81x4 - 126 x²y² + 49y4 

(8a2b + 7ab6y²)² = (8a²b)² + 2(8a²b)(7ab6y²) + (7ab6y²)²

= 64a4b² + 112a3b7y² + 49a²b12y4 

20. (15x²y - 3xy²z6)² =

= (15x²y)² - 2(15x²y)(3xy²z6) + (3x²z6)²

= 225x4y² - 90x²y3z6 + 9x4z12 

21. (2a - 3b)² + (3a - 5b)² =

= [4a²-2(2a)(3b)+ 9b²] + [9a² - 2(3a)(5b) + 25b²]

= 4a² - 12ab + 9b² + 9a² - 30ab + 25b²

= 13a² - 42ab + 31b²

22. (11x - 5y)² - (13x + 3y)² + (x - 2y)²=

= (121x² - 2(11x)(5y) + 25y²) - (169x²+ 2 (13x)(3y) + 9y²) + (x² - 2(x)(2y) + 4y²)

= 121x² - 110xy + 25y² - 169x² - 78xy - 9y² + x² - 4xy + 4y²

= - 47x² - 192xy - 20y²

23. [a/2 + 2b]² + [2a – b/2]²=[(a²/4+2(a/2(2b)+4b²]+[4a²-2(2a)(b/2+b²/4]

= a²/4 + 4ab/² + 4b² + 4a² - 4ab/2 + b² /4

= a²/4 + 8ab + 4b² + b²/4

= a² + 16a² /4 + 16b² + b²/4

= 17a²/4 + 17b²/4 

24. (3a - b/5)² = 9a² - 2(3a)(b/5) + b²/25

= 9a²- 6ab/5 + b²/25

(2x²/3 - 3yz/5 )² =

= 4x4 /9 - 2(2x²/3)(3yz/5) + (9x²y²/25)

= 4x4 /9 - 12x²yz/15 + 9x²y²/25

= 4x4 /9 - 4x²yz/5 + 9x²y²/25

(0,1a² - 0,2abc)² =

=(1a²/10 - 2abc/10)²

=(1a²/10)² - 2(1a²/10)(2abc/10) + (2abc/10)²

= a4/100 - 4a³bc/100 + 4a²b²c²/100

= 0,01a4 - 0,04a²