Respuestas
x= -1/3 ; x=8 ; sol=( 14,∞) ; sol =( -7 ,∞) ; [-1, ∞); [ 40, ∞ ) ; x = -12 ; sol = ( -∞, 402/1633]
Para resolver las ecuaciones y las desigualdades fraccionarias, se procede a despejar el valor de x, si es una desigualdad el resultado es un intervalo de la siguiente manera :
8x -11 = 5x-12
8x -5x = -12 +11
3x = -1
x = -1/3
6x +4 = 4*( x +5)
6x + 4 = 4x+20
6x -4x = 20-4
2x = 16
x = 16/2
x = 8
7x -6 ∠ 6x +8
7x -6x ∠ 8 +6
x ∠ 14
sol = ( 14 , ∞)
5x +7 >2x-12
5x -2x > -12-9
3x > -21
x >-21/3
x > -7
sol = ( -7, ∞ )
7x +7 ≥ 6*( x -1 )
7x +7 ≥ 6x -6
7x -6x ≥-6 -7
x ≥ -1
sol =[ -1, ∞)
6x +5 ≤ 5 *( x-9)
6x + 5 ≤ 5x -45
6x -5x ≤ -45-5
x ≤40
Sol = [ 40 , ∞)
( 4x +2)/6 = ( 5x -1 )/8
8* ( 4x +2) = 6*( 5x -1)
32x +16 = 30x -6
32x -30x = -6-16
2x = -24
x = -24/2
x = -12
( 6x +1 )/10 - (5-7x)/6 ≤( -8-7x)/17+ 10x/9 mcm= 1530
153* ( 6x +1) - 255*( 5-7x ) ≤ 90*( -8-7x) + 1700x
918x +153 - 1275 + 1785x ≤- 720 - 630x +1700x
1633x ≤ 402
x ≤402/1633
sol = (-∞, 402/1633]
Respuesta:
Explica 8x -11 = 5x-12
8x -5x = -12 +11
3x = -1
x = -1/3
6x +4 = 4*( x +5)
6x + 4 = 4x+20
6x -4x = 20-4
2x = 16
x = 16/2
x = 8
7x -6 ∠ 6x +8
7x -6x ∠ 8 +6
x ∠ 14
sol = ( 14 , ∞)
5x +7 >2x-12
5x -2x > -12-9
3x > -21
x >-21/3
x > -7
sol = ( -7, ∞ )
7x +7 ≥ 6*( x -1 )
7x +7 ≥ 6x -6
7x -6x ≥-6 -7
x ≥ -1
sol =[ -1, ∞)
6x +5 ≤ 5 *( x-9)
6x + 5 ≤ 5x -45
6x -5x ≤ -45-5
x ≤40
Sol = [ 40 , ∞)
( 4x +2)/6 = ( 5x -1 )/8
8* ( 4x +2) = 6*( 5x -1)
32x +16 = 30x -6
32x -30x = -6-16
2x = -24
x = -24/2
x = -12