Question

(3x7-4x6+9x5+30x2-38x+91)÷(3x2-4x+9) ayuedenme a resolverlo

Answer 1

$((3 \times 7) - (4 \times 6) + (9 \times 5) + (30 \times 2) - (38 \times 91)) \div ((3 \times 2) - (4 \times 9))$

$((21) - (24) + (45) + (60) - (3458) \div ((6) - (36))$

$\frac{(21 - 24 + 45 + 60 - 3458)}{(6 - 36)}$

operando

$\frac{ - 3356}{ - 30}$

simplificar

$\frac{1678}{15}$