• Asignatura: Matemáticas
  • Autor: andyyperez1999
  • hace 8 años

Resolver la Ecuaciones :
3 (2x- 6) -[ (x-( 3x-8) +2) -1 ] = 2 ( 3- 2x)

Respuestas

Respuesta dada por: belenletras
0

- Tarea:

Resolver la ecuación:

3 . (2x - 6) - [ (x - (3x-8) +2) - 1 ] = 2 . (3 - 2x)

- Solución:

Resolvemos la ecuación:

3 . (2x - 6) - [ (x - (3x-8) +2) - 1 ] = 2 . (3 - 2x)

3 . (2x - 6) - [ (x -3x +8 + 2) - 1 ] = 2 . (3 - 2x)

3 . (2x - 6) - [ -2x + 10 - 1 ] = 2 . (3 - 2x)

3 . (2x - 6) - (-2x + 9) = 2 . (3 - 2x)

6x - 18 + 2x - 9 = 6 - 4x

8x - 27 = 6 - 4x

8x + 4x = 6 + 27

12x = 33

x = 33/12

x = 11/4

El número es 11/4.

Comprobamos la ecuación:

3 . (2x - 6) - [ (x - (3x-8) +2) - 1 ] = 2 . (3 - 2x)

3 . (2 . 11/4 - 6) - [ (11/4 - (3 . 11/4 - 8) + 2) - 1 ] = 2 . (3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [ (11/4 - (3.11/1.4 - 8) + 2) - 1 ] = 2 . ( 3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [ (11/4 - (33/4 - 8/1) + 2) - 1 ] = 2 . (3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [ (11/4 - (4:4.33-4:1.8/4) + 2) - 1] = 2 . (3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [ (11/4 - (33-32/4) + 2) - 1 ] = 2 . ( 3 - 2 . 11/4)

3 . ( 2 . 11/4 - 6) - [ (11/4 - 1/4 + 2/1) - 1 ] = 2 . ( 3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [ (4:4.11-4:4.1+4:1.2/4) - 1] = 2 . (3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [(11-1+8/4) - 1] = 2 . ( 3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - [18/4 - 1/1] = 2 . (3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - (4:4.18-4:1.1/4) = 2 . ( 3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - (18-4/4) = 2 . ( 3 - 2 . 11/4)

3 . (2 . 11/4 - 6) - 14/4 = 2 . (3 - 2 . 11/4)

3 . (2.11/1.4 - 6) - 14/4 = 2 . ( 3 - 2.11/1.4)

3 . (22/4 - 6/1) - 14/4 = 2 . (3/1 - 22/4)

3 . (4:4.22-4:1.6/4) - 14/4 = 2 . (4:1.3-4:4.22/4)

3 . (22-24/4) - 14/4 = 2 . (12-22/4)

3 . (-2/4) - 14/4 = 2 . (-10/4)

3.-2/1.4 - 14/4 = 2.-10/1.4

-6/4 - 14/4 = -20/4

-6-14/4 = -20/4

-20/4 = -20/4

-5/1 = -5/1

-5 = -5

Preguntas similares