Question

Si cos(θ)=3/9, bosqueje un triángulo rectángulo con ángulo θ agudo y halle el valor de

csc(θ) + tan(θ)

Answer 1

$csc(\theta) = \frac{9}{6 \sqrt{2} } = \frac{3 \sqrt{2} }{4}$
$tan(\theta) = 2 \sqrt{2}$
$csc(\theta) + \tan(\theta) = \frac{3 \sqrt{2} }{4} + 2 \sqrt{2}$
$csc(\theta) + \tan(\theta) = \frac{3 \sqrt{2} }{4} + \frac{8 \sqrt{2} }{4}$
$csc(\theta) + \tan(\theta) = \frac{11 \sqrt{2} }{4}$