Question

Cacular E=(Sen18° + Cos12°)² + (Sen12°+Cos18°)²

Answer 1

Sen18°=0,31
Cos12°=0,98
0,31+0,98=1,29
1,29*1,29=1,66

Sen12°=0,21
Cos18°=0,95
0,21+0,95=1,16
1,16*1,16=1,35

E=1,66+1,35
E=3,01