Question

necesito ayuda en álgebra plis

Answer 1

Respuesta:

Espero que te sirva. :D

1.) 6

2.) 40

3.) 84

4.) 127

5.) 243

6.) 20

Explicación paso a paso:

1.) $6^{0}+(-2)^{4}-(\frac{1}{3})^{-2}-(\frac{1}{2})^{-1} = 1+16-3^{2}-2=1+16-9-2=6$

2.) $3^{0}+3^{-1} +3^{-2}+3^{-3}=1+\frac{1}{3}+\frac{1}{3^{2}}+\frac{1}{3^3}}=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}=40$

3.) $\frac{5^{4}}{5^{2}}+\frac{3^{7}}{3^{4}}+\frac{2^{9}}{2^{4}}=5^{2}+3^{3}+2^{5}=25+27+32=84$

4.) $(\frac{1}{6})^{-2}+(\frac{1}{3})^{-3}+(\frac{1}{4})^{-3}=6^{2}+3^{3}+4^{3}=36+27+2^{6}=36+27+64=127$

5.) $(3^{4})^{4}-(3^{8})^{2}+(3^{5})^{1}=3^{16}-3^{16}+3^{5}=3^{5}=243$

6.) $(\frac{1}{6})^{-2}-(\frac{1}{2})^{-5}+4^{2}=6^{2}-2^{5}+2^{4}=(3*2)^{2}-2^{5}+2^{4}=3^{2}*2^{2}-2^{5}+2^{4}=(3^{2}-2^{3}+2^{2})*2^{2}=(9-8+4)*4=5*4=20$