Question

Por favor necesito ayuda con estoooooo

Answer 1

Respuesta:

1. $\frac{1-\frac{3}{4} }{1+\frac{1}{8} }=\frac{\frac{1}{4} }{\frac{9}{8} }=\frac{2}{9}$

2.$(\frac{3}{5} + \frac{1}{2} + \frac{7}{10})/\frac{3}{4}   = \frac{12}{5}$

3. $\frac{2}{5}(6-\frac{3}{2})= \frac{9}{5}$

4. $0.75(\frac{8}{9} +\frac{1}{3})=\frac{11}{12}$

5. $(1-\frac{3}{4})(3-\frac{5}{2})=\frac{1}{8}$

6. $2(\frac{5}{4}-\frac{1}{2})+3(\frac{1}{2}-\frac{1}{3})=2$

7. $\frac{3}{4}+\frac{1}{6} -\frac{11}{12} = 0$

8. $\frac{5}{8} +\frac{3}{4} -\frac{1}{6} -\frac{2}{3} =\frac{13}{24}$

9. $\frac{\frac{2}{5} +\frac{1}{2} }{\frac{1}{10} +\frac{1}{5} } = 3$

10. $\frac{\frac{1}{6} }{\frac{1}{8} - \frac{1}{9} } = 12$

Evalúe la expresión:

$5^{4}. 5^{-2} = 5^{2} = 25\\\frac{3}{3^{-2}}=3^{3}= 27\\ (\frac{5}{3})^{0}*2^{-1} = 1*\frac{1}{2} = \frac{1}{2} \\ (\frac{1}{4})^{-2}=(2^{-2})^{-2} = 2^{4}=16\\(\frac{-2}{3})^{-3}= (\frac{3^{-1}}{-2^{-1}})^{-3}=\frac{-27}{8}\\   (\frac{4}{9})^{-1/2}=\sqrt{(\frac{4}{9})^{-1} } = \sqrt{\frac{9^{-1}}{4^{-1}} } = \frac{3}{2}   \\\frac{x^{6}}{x^{10}}=x^{-4}=\frac{1}{x^{4}}$