• Asignatura: Química
  • Autor: antoniolope29
  • hace 8 años

Porfavor Necesito más Ayuda en la Tabla

Adjuntos:

Respuestas

Respuesta dada por: snorye
1

3

a. KMnO4

  K: 1 x 39,09 = 39.09 g/mol

Mn: 1 x 54,93 = 54,93 g/mol

  O: 4 x 16  =   64g/mol

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               PM = 158.02 g/mol

b. H3PO4

H: 3 x 1 = 3 g/mol

P: 1 x 39.07 = 30.97 g/mol

O: 4 x 16 = 64 g/mol

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            PM = 97.97 g/mol

c. MnCl2

Mn: 1 x 54,93 = 54,93 g/mol

Cl: 2 x 35,45 = 70.9 g/mol

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               PM = 125.83 g/mol

d.  KCl

K:  1 x 39,09 = 39.09 g/mol

Cl:  1 x 35,45 = 35.45 g/mol

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                PM = 74.57 g/mol

4.

sustancia: KCl

fórmula:n = masa/PM

Mm KCl = 74.57 g/mol

a) 2 moles

masa = 2 mol x 74.57 g/mol

masa = 149.08 g KCl

b) 3.5 moles

masa = 3.5 mol x 74.57 g/mol

masa = 260.995 g KCl

sustancia: KMnO4

PM KMnO4 = 158.02 g/mol

a) 2 moles

masa = 2 mol x 158.02 g/mol

masa = 315.04 g KMnO4

b) 3.5 moles

masa = 3.5 mol x 158.02 g/mol

masa = 553.07  g KMnO4



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