Question

despejar : a , v , y0

y=y0+v×t+1/2 (a× r^2)

Answer 1

despeje de a

y-1/2(ar^2) = yo+vt

-1/2(ar^2) = yo+vt-y

-1(ar^2) = 2(yo+vt-y)

-ar^2 = 2(yo+vt-y)

a= [2(yo+vt-y)]/(-r^2)

despeje de v

y-vt=yo+1/2(ar^2)

vt= yo+1/2(ar^2)-y

v= [yo+1/2(ar^2)-y]/t

despeje de yo

y-yo = vt+1/2(ar^2)

-yo = vt+1/2(ar^2)-y

yo= y-vt-1/2(ar^2)

Espero y te haya sido de ayuda :p