Question

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Inside a 10 L tank, there is a specific quantity of gas at 200 000 Pa. If at constant temperature the volume is reduced to 8 L using a piston, what pressure will the gas be under?

Answer 1

aplicar la Ley de Boyle

V1 x P1 = V2 x P2

V1 ? 10 L

P1 = 200000 Pa

1 atm ------ 101325 Pa

   x   ------  200000 Pa

x = 1.973 atm

V2 = 8 L

P2 = ¿?

Calcular P2

P2 = (10 L x 1.973 atm ) 8 L

P2 = 2.47 atm

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P2 ( 10 L x 200000 Pa) / 8 L

P2 = 250000 Pa