• Asignatura: Química
  • Autor: stefymurillo79
  • hace 8 años

Realizar las siguientes reacciones y encontrará los pesos moleculares. CLORURO DE RADIO + ÁCIDO TELÚRICO Y TELURATO DE RADIO+ ÁCIDO CLORHIDRICO

Respuestas

Respuesta dada por: snorye
0

CLORURO DE RADIO + ÁCIDO TELÚRICO Y TELURATO DE RADIO+ ÁCIDO CLORHIDRICO

                        RaCl2 + H2TeO4 → RaTeO4 + 2HCl

Pesos moleculares:

RaCl2

Ra:  1 x 223,01 = 223,01 g/mol

Cl: 2 x 35.45 = 70.9 g/mol

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               Mm = 293.91 g/mol

H2TeO4

H:  2 x 1 = 2 g/mol

Te: 1 x 127,60 = 127,60 g/mol

O: 4 x 16 = 64 g/mol

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                 Mm = 193.60 g/mol

RaTeO4

Ra: 1 x 223,01 = 223,01 g/mol

Te: 1 x 127,60 = 127,60 g/mol

O: 4 x 16 = 64 g/mol

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                 Mm = 414.61 g/mol

HCl

H:  1 x 1 = 1 g/mol

Cl:  1  x 35.45 = 35.45 g/mol

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                Mm = 36.45 g/mol

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