Realizar las siguientes reacciones y encontrará los pesos moleculares. CLORURO DE RADIO + ÁCIDO TELÚRICO Y TELURATO DE RADIO+ ÁCIDO CLORHIDRICO
Respuestas
CLORURO DE RADIO + ÁCIDO TELÚRICO Y TELURATO DE RADIO+ ÁCIDO CLORHIDRICO
RaCl2 + H2TeO4 → RaTeO4 + 2HCl
Pesos moleculares:
RaCl2
Ra: 1 x 223,01 = 223,01 g/mol
Cl: 2 x 35.45 = 70.9 g/mol
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Mm = 293.91 g/mol
H2TeO4
H: 2 x 1 = 2 g/mol
Te: 1 x 127,60 = 127,60 g/mol
O: 4 x 16 = 64 g/mol
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Mm = 193.60 g/mol
RaTeO4
Ra: 1 x 223,01 = 223,01 g/mol
Te: 1 x 127,60 = 127,60 g/mol
O: 4 x 16 = 64 g/mol
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Mm = 414.61 g/mol
HCl
H: 1 x 1 = 1 g/mol
Cl: 1 x 35.45 = 35.45 g/mol
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Mm = 36.45 g/mol