Question

1. Calcula el valor numérico del polinomio p(x)= $2x^{3}$-5x+3 per a x=0,x= -1 i x=$\frac{1}{2}$.

Answer 1

Hola :D

$p(x) = 2 {x}^{ 3} - 5x + 3 \: \: \: \: \: \: \: \: \: \: \: \: \: x = 0 \\ p(0) = 2 {(0)}^{3} - 5(0) + 3 \\ p(0) = 3$


$p(x) = 2x {}^{3} - 5x + 3 \: \: \: \: \: \: \: \: \: \: x = - 1 \\ p( - 1) = 2 {( - 1)}^{3} - 5( - 1) + 3 \\ p( - 1) = 2( - 1) + 5 + 3 \\ p( - 1) = -2 + 8 \\ p( - 1) = 6$



$p(x) = 2 {x}^{3} - 5x + 3 \: \: \: \: \: \: \: \: \: \: \: \: \: x = \frac{1}{2} \\ p( \frac{1}{2} ) = 2( \frac{1}{2} ) {}^{3} - 5( \frac{1}{2} ) + 3 \\ p( \frac{1}{2} ) = 2( \frac{1}{8} ) - \frac{5}{2} + 3 \\ p( \frac{1}{2} ) = \frac{2}{8} - \frac{5}{2} + 3 \\ p( \frac{1}{2} ) = \frac{4 - 40}{16} + 3$


$p( \frac{1}{2} ) = - \frac{36}{16} + \frac{48}{16} \\ p( \frac{1}{2} ) = \frac{12}{16} \\ p( \frac{1}{2} ) = \frac{3}{4}$



Espero haberte ayudado,

SALUDOS CORDIALES, AspR178 !!! ✌️^_^⭐