Question

Hola!
alguien me puede ayudar con esto porfa!!!
gracias!!!

Answer 1

SOLUCIÓN

Hola!! :D

Recordemos algunas propiedades

            $\mathbb{\boldsymbol{FRACCIONES}}\\\\\\\boxed{\mathrm{\dfrac{a}{b} + \dfrac{c}{d} = \dfrac{ad + cb}{bd}}}\\\\\\\boxed{\mathrm{\dfrac{a}{c} +\dfrac{b}{c} = \dfrac{a+b}{c}}}\\\\\\\boxed{\mathrm{ \frac{a}{b} \times \frac{c}{d}=\frac{a\times c}{b\times d}}}$

                           $(\dfrac{3}{5} -1)^{2} + \sqrt{\dfrac{2}{3}} \times \sqrt{\dfrac{8}{3}} -\dfrac{\sqrt{(\frac{17}{3}+ \frac{8}{3})\times\frac{22}{27}}}{-\sqrt{1+\frac{7}{9}}} \\ \\ \\ (\dfrac{3-5}{5})^{2} + \sqrt{\dfrac{2}{3}} \times 2\sqrt{\dfrac{2}{3}} -\dfrac{\sqrt{(\frac{17+8}{3})\times\frac{22}{27}}}{-\sqrt{\frac{9+7}{9}}} \\ \\ \\(\dfrac{-2}{5})^{2} + 2(\sqrt{\dfrac{2}{3}})^{2} -\dfrac{\sqrt{\frac{25}{3}\times\frac{22}{27}}}{-\sqrt{\frac{16}{9}}}$

                          $\dfrac{4}{25} + 2(\dfrac{2}{3}) -\dfrac{\sqrt{\frac{25}{3}\times\frac{22}{27}}}{-\frac{4}{3}} \\\\\\\dfrac{4}{25} + \dfrac{4}{3} -\dfrac{\frac{5\sqrt{22}}{9}}{-\frac{4}{3}}\\\\\\\dfrac{4}{25} + \dfrac{4}{3} -\dfrac{-15\sqrt{22}}{36}\\\\\\\dfrac{4}{25} + \dfrac{4}{3} -\dfrac{-5\sqrt{22}}{12}\\\\\\\dfrac{4}{25} + \dfrac{4}{3} +\dfrac{5\sqrt{22}}{12}\\\\\\\dfrac{48}{300} + \dfrac{400}{300} +\dfrac{125\sqrt{22}}{300} \\\\\\\boxed{\boldsymbol{\dfrac{480 + 125\sqrt{22}}{300}}}$