Question

Cual es la presion en mmHg de un gas ideal si 0,787 moles ocupan un volumen de 1880 ml a la temperatura de -232 c

Answer 1

PV = nRT

P = nRT/V

n = 0.787 moles

R = 0.082 L*atm/mol*K

T = -232ºC = 41.15K

V = 1880mL = 1.88L

P = (0.787 * 0.082 * 41.15)/1.88

P = 2.65/1.88

P = 1.88 atm

1.88 atm * 760mmHg/1atm = 1428.8 mmHg