Question

ayudenme por favor..

Answer 1

Respuesta:

$\frac{21}{2}-\sqrt{\frac{12}{13}}$

Explicación paso a paso:

M = 2 - $\frac{1}{4}+4-\frac{\sqrt{12} }{\sqrt{13}}+\frac{8^{2/3}}{2}$

M = $\frac{8}{4}-\frac{1}{4}-\sqrt{\frac{12}{13}}+\frac{(2^{3})^{2/3}}{2}$

M = $\frac{7}{4}+4-\sqrt{\frac{12}{13}}+\frac{2^{2}}{2}$

M = $\frac{7}{4}+4-\sqrt{\frac{12}{13}}+2$

M = $\frac{7}{4}+6-\sqrt{\frac{12}{13}}$

M = $\frac{7}{4}+\frac{24}{4}-\sqrt{\frac{12}{13}}$

M = $\frac{31}{4}-\sqrt{\frac{12}{13}}$

N = $2^{-1}.3^{-1}$

N = $\frac{1}{2}-\frac{1}{3}$

N = $\frac{3-2}{6}$

N = 1/6

(M - 3/4).(N + 4/3)

($\frac{31}{4}-\sqrt{\frac{12}{13}}-\frac{3}{4}).(\frac{1}{6}+\frac{4}{3})$

$(\frac{28}{4}-\sqrt{\frac{12}{13}}).(\frac{1+8}{6})$

$(7-\sqrt{\frac{12}{13}}).(\frac{9}{6})$

$(7-\sqrt{\frac{12}{13}}).(\frac{3}{2})$

$\frac{21}{2}-\sqrt{\frac{12}{13}}$