Question

si xΔy = x^{2} + y^{2} + xy
calcular Q
( 3Δ2 ) + a+ ( 5Δ1 ) = 7 Δ 4

Answer 1

Respuesta:

a=43

Explicación paso a paso:

( 3Δ2 )= 3^{2} + 2^{2} + 3*2= 19

( 5Δ1 ) =  5^{2} + 1^{2} + 5*1=31

7 Δ 4= 7{2} + 4^{2} + 7*4=93

19+a+31=93

a=43