Question

Alguien q me resuelva las ecuaciones plisss

Answer 1

Respuesta:

a     y₁ = -3        y₂ = -2

b     x₁ = -1/3     x₂ = 7/2

Explicación paso a paso:

a

y(y+5) = -6

y² + 5y = -6

y² + 5y + 6 = 0

y = {-5 -+√(5²-(4*1*6))} / (2*1)

y = {-5-+√(25-24)} / 2

y = {-5-+√1}/2

y = {-5-+1}/2

y₁ = {-5-1}/2 = -6/2 = -3

y₂ = {-5+1}/2 = -4/2 = -2

Comprobación:

-3(-3+5) = -3*2 = -6

-2(-2+5) = -2*3 = -6

b

6x² - 19x = 7

6x² - 19x -7 = 0

x = {19-+√(-19² - (4*6*-7))} / (2*6)

x = {19-+√(361+168)}/12

x = {19-+√529}/12

x = {19-+23}/12

x₁ = {19-23}/12 = -4/12 = -1/3

x₂ = {19+23}/12 = 42/12 = 21/6 = 7/2

Comprobación:

6(-1/3)² - 19(-1/3) = 7

6/9 + 19/3 = 6/9 + 57/9 = 63/9 = 7

6(7/2)² - 19(7/2) = 6*49/4 - 133/2 = 294/4 - 266/4 = 28/4 = 7