Question

(2x+1)(x-1)+χ²=3(x-1)(x+2)-3

Answer 1

$(2x + 1)(x - 1) + {x}^{2} = 3(x - 1)(x + 2) - 3 \\ 2 {x}^{2} - 2x + x - 1 + {x }^{2} = 3( {x}^{2} + 2x - x - 2) - 3 \\ 3 {x }^{2} - x - 1 = 3( {x }^{2} + x - 2) - 3 \\ 3 {x }^{2} - x - 1 = 3 {x}^{2} + 3x - 6 - 3 \\ 3 {x }^{2} - x - 1 = 3 {x}^{2} + 3x - 9 \\ 3 {x}^{2} - 3 {x}^{2} - x - 3x = - 9 + 1 \\ - 4x = - 8 \\ x = \frac{ - 8}{ - 4} \\ x = 2$