Question

$9 {}^{2} \div 3 + \sqrt{121} \times 3 - (2 {}^{3} ) {}^{2} \div 4$
$16 \div (2 + 6) + \sqrt{3 {}^{2} } +4 {}^{2} - (4 - 3) {}^{2}$

Answer 1

Respuesta:

1) 44

2) 20

Explicación paso a paso:

1) $9^{2}$ ÷ 3 + $\sqrt{121}$ x 3 - $(2^{3})^{2}$ ÷ 4

81 ÷ 3 + 11 x 3 - $2^{6}$ ÷ 4

27 + 33 - 64 ÷ 4

60 - 16

44

2) 16 ÷ (2 + 6) + √($3^{2}$) + $4^{2}-(4-3)^{2}$

16 ÷ 8 + 3 + 16 - $1^{2}$

2 + 3 + 16 - 1

20