división de la regla ruffini de x3-x2-x+4÷x+2

Respuestas

Respuesta dada por: tellocamila7mob
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Respuesta:ni idea  Explicación paso a paso:

Respuesta dada por: jahirolopezpcpd1f
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Respuesta:


Explicación paso a paso:


P(x) = 4x2 - 1 Q(x) = x3 - 3x2 + 6x - 2 R(x) = 6x2 + x + 1 S(x) = 1/2x2 + 4 T(x) = 3/2x2 +5 U(x) = x2 + 2

Calcular:

1P(x) + Q (x) = = (4x2 - 1) + ( x3 - 3x2 + 6x - 2) = = x3 - 3x2 + 4x2+ 6x - 2 - 1 = = x3 + x2+ 6x - 3 2P(x) - U (x) = = (4x2 - 1) - (x2 + 2) = = 4x2 - 1 - x2 - 2 = = 3x2 - 3 3P(x) + R (x) = = (4x2 - 1) + (6x2 + x + 1) = = 4x2 + 6x2 + x - 1 + 1 = = 10x2 + x 42P(x) - R (x) = = 2(4x2 - 1) - (6x2 + x + 1) = = 8x2 - 2 - 6x2 - x - 1 = = 2x2 - x - 3 5S(x) + R (x) + U(x) = = (1/2 x2 + 4 ) + (3/2 x2 +5 ) + (x2 + 2) = = 1/2 x2 + 3/2 x2 + x2 + 4 + 5+ 2 = = 3x2 + 11 6S(x) - R (x) + U(x) = = (1/2 x2 + 4 ) - (3/2 x2 +5 ) + (x2 + 2) = = 1/2 x2 + 4 - 3/2 x2 - 5 + x2 + 2

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