Se queman 10 g de sulfano en condiciones normales, produciéndose agua y trióxido de azufre:
a) Escribe y ajusta la reacción.
b) Halla la cantidad de moles y litros de agua y trióxido de azufre gas obtenidos.
Respuestas
Se queman 10 g de sulfano en condiciones normales, produciéndose agua y trióxido de azufre:
a) Escribe y ajusta la reacción.
H6S + 3 O2 → SO3 + 3 H2O
b) Halla la cantidad de moles y litros de agua y trióxido de azufre gas obtenidos.
Mm H6S = 38 g/mol
n H2O = 10 g H6S x 1 mol H6S x 3 mol H2O
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38 g H6S 1 mol H6S
n H2O = 0.789 moles
calcular Litros de agua
V H2O = 10 g H6S x 1 mol H6S x 3 mol H2O x 22.4 L H2O
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38 g H6S 1 mol H6S 1 mol H2O
V H2O = 17.68 Litros
2. calcular moles de SO3
n SO3 = 10 g H6S x 1 mol H6S x 1 mol SO3
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38 g H6S 1 mol H6S
n SO3 = 0.263 moles
calcular Litros de agua
V SO3 = 10 g H6S x 1 mol H6S x 1 mol SO3 x 22.4 L SO3
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38 g H6S 1 mol H6S 1 mol SO3
V SO3 = 5.895 Litros