Question

p(x) = 6x3 - 3x2 - x - 5 y q(x) = x2 + 2x + 4 calcula

c. p(x) . q(x)

d. (q(x))3
ayudennnn

Answer 1

Explicación paso a paso:

c) p(x) . q(x) = $(6x^{3} - 3x^{2} -x-5) . (x^{2} +2x+4)=6x^{5} +12x^{4} +24x^{3} -3x^{4} -6x^{3} -12x^{2} -x^{3} -2x^{2} -4x-5x^{2} -10x-20= 6x^{5} +9x^{4 } +17x^{3} -19x^{2} -14x-20$

$(q(x))^{3} = (x^{2}+2x+4) ^{3} = (x^{2}+2x+4) . (x^{2}+2x+4) . (x^{2}+2x+4) = (x^{4} +2x^{3} +4x^{2} +2x^{3} +4x^{2} +8x+4x^{2} +8x+16).(x^{2}+2x+4) = (x^{4} +4x^{3} +12x^{2} +16x+16).(x^{2}+2x+4)=x^{6} +2x^{5} +4x^{4} +4x^{5} +8x^{4} +16x^{3} +12x^{4}+24x^{3} +48x^{2} +16x^{3} +32x^{2}+64x+16x^{2} +32x+64=x^{6} +6x^{5} +24x^{4} +56x^{3} +96x^{2} +96x+64$