Question

ayuds pliss urgenteee

Answer 1

• Segundo problema

$\frac{1}{3} ( \frac{2x - 3}{6} + \frac{2x - 2}{6} ) = \frac{1}{12} ( \frac{9x - 12 - 2x + 7}{3} ) \\ \\ \frac{1}{3} ( \frac{4x - 5}{6} ) = \frac{1}{12} ( \frac{7x - 5}{3} ) \\ \\ 4x - 5 = \frac{7x - 5}{2} \\ 8x - 10 = 7x - 5 \\ x = 5$

• Primer problema

$\frac{2}{3} (\frac{2x + 1}{2} ) - 5( \frac{5x + 1}{15} ) = \frac{2}{5} \\ \\ \frac{2x + 1}{3} - (\frac{5x + 1}{3} ) = \frac{2}{5} \\ \\ \frac{ - 3x}{3 } = \frac{2}{5} \\ \\ - 15x = 6 \\ - 3x = 2 \\ x = - \frac{2}{3}$