Question

Halle la raiz de cada una de las siguientes expresiones:
√9 .....4√625 ........... √144........√81...........7√128..........5√32

Answer 1

La forma más facil es descomponer las cantidades en factores primos...

$\sqrt{9}= \sqrt{3X3} =\sqrt{3^{2}  } = 3 \\\\\\4\sqrt{625}=4 \sqrt{25X25}=4 \sqrt{5^{2}X5^{2} } =4X5X5 =100\\\\\sqrt{144}= \sqrt{12^{2}} =12\\\\\sqrt{81}= \sqrt{3^{2} X3^{2} } =3X3=9\\\\7\sqrt{128}=7 \sqrt{2^{2}X2^{2}X2^{2}X2}  =7X2X2X2\sqrt{2} =56\sqrt{2} \\\\\\5\sqrt{32} =5\sqrt{2^{2} X2^{2} X2} =5X2X2\sqrt{2} =20\sqrt{2}$

3|3

Answer 2

√9 =3

4√625=5

√144=12

√81=9

7√128=2

5√32=2