Question

Determina la composición centesimal de la sacarosa

Answer 1

Determina la composición centesimal de la sacarosa (C12H22O11)

1. calcular Mm de la Sacarosa

C: 12 x 12 = 144 g/mol

H: 22 x 1 = 22 g/mol

O: 11 x 16 = 176 g/mol

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        Mm = 342 g/mol

2. calcular % C

         342 g ---- 100 %

          144 g -----     x

             x = 42.11 % C

3. calcular % H

               342 g ---- 100 %

                 22 g -----     x

             x = 6.43 % H

4. calcular %O

             342 g ---- 100 %

              176 g -----     x

             x = 51.46 % O