Question

(x-2)^2 > (x+2)(x-2)+8

Answer 1

$(x - 2)^{2} > (x + 2)(x - 2) + 8 \\ {x}^{2} - 2(2)(x) + 4 > {x}^{2} - 4 + 8 \\ - 4x + 4 > 4 \\ - 4x > 0 \\ 0 > 4x \\ 0 > x$