Question

$(x+4)^{2} +(x-4)^{2} -2(x-2)(x+2)$

Answer 1

(x+4)2+(x−4)2−2(x−2)(x+2)​    

(x+4)2= 2+8x+16  

=x2+8x+16+(x−4)2−2(x−2)(x+2)  

(x−4)2= x2−8x+16  

=x2+8x+16+x2−8x+16−2(x−2)(x+2)    

Expandir: −2(x−2)(x+2)= −2x2+8

$=x^2+8x+16+x^2-8x+16-2x^2+8$

=x2+8x+16+x2−8x+16−2x2+8  

Simplificar: x2+8x+16+x2−8x+16−2x2+8= 40  

=40

R/ 40