Question

2/5 *(-4/3)-1/9
3/4-(2/5+((2/5+3/5)-(1/6+1/2))
con procedimiento por vafor

Answer 1

$\frac{2}{5}(-\frac{4}{3})-\frac{1}{9} =-\frac{8}{15}-\frac{1}{9}=-\frac{24+5}{45}=-\frac{29}{45}\\\frac{3}{4}-(\frac{2}{5}+((\frac{2}{5}+\frac{3}{5})-(\frac{1}{6}+\frac{1}{2})))=\frac{3}{4}-(\frac{2}{5}+((\frac{2+3}{5})-(\frac{1+3}{6})))=\frac{3}{4}-(\frac{2}{5}+(1-\frac{4}{6}))=\frac{3}{4}-(\frac{2}{5}+1-\frac{2}{3})=\frac{3}{4}-(\frac{6+15-10}{15})=\frac{3}{4}-\frac{11}{15}=\frac{45-44}{60}=\frac{1}{60}$

saludos...