3 [2x+1-2(2x-1)]+4 = 2[1+2(3-x)]

Respuestas

Respuesta dada por: jkarlos
17
3 [2x+1-2(2x-1)]+4 = 2[1+2(3-x)]
3 [2x+1-4x+2]+4 = 2[1+6-2x]
3 [2x-4x+2+1]+4 = 2[7-2x]
3 [-2x+3]+4 = 14-4x
-6x+9+4 = 14-4x
-6x+13=14-4x
-6x+4x=14-13
-2x=1
x= -
       2

la solucion es x= -1/2
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