Question

halla la tasa de variacion en el intervalo [2,3] en cada una de las siguientes funciones

Answer 1

a) TV = $\frac{1(3)-1(2)}{3-2}= \frac{3-2}{1} =\frac{1}{1}=1$

b) TV = $( (3^{4} - 3^{3})- (2^{4}- 2^{3}))/3-2$

TV = $\frac{(81-27)-(16-8)}{1}$

TV = $\frac{54-8}{1}= \frac{46}{1} = 46$

C)

TV = (2$((2(3)^{3} - 3(3)^{2} )-(2(2)^{3}-3 (2)^{2}))/3-2$

TV = $\frac{(2(27)-3(9))-(2(8)-3(4))}{1}$

TV=$\frac{(54-27)-(16-12)}{1}$

TV = 27-4 = 23

d)

TV = ($((\sqrt{2(3)-1}-1 )-(\sqrt{2(2)-1}-1))/2-1$

TV=(($\sqrt{6-1} -1)-(\sqrt{4-1} -1))/1$

TV = (($\sqrt{5}-1)-( \sqrt{3}-1)$

TV = (2,2 - 1) - (1,73 - 1)

TV = 1,2 - 0,73

TV = 0,47

Answer 2

Respuesta:

a) TV =  

b) TV =  

TV =  

TV =  

C)

TV = (2

TV =  

TV=

TV = 27-4 = 23

d)

TV = (

TV=((

TV = ((

TV = (2,2 - 1) - (1,73 - 1)

TV = 1,2 - 0,73

TV = 0,47