Question

(5y-6) /2 =y- (2-y) /3

Answer 1

$\frac{5y-6}{2}=y- \frac{2-y}{3} \\ \\ \frac{5y-6}{2}=\frac{3y-2+y}{3} \\ \\ 15y-18=6y-4+2y \\ 15y-6y-2y=18-4 \\ 7y=14 \\ \\ y= \frac{14}{7}=2$

Answer 2

$\frac{(5y-6)}{2}= y- \frac{(2-y)}{3} \\ \\ \frac{(5y-6)}{2}= \frac{3y}{3}- \frac{(2-y)}{3} \\ \\ \frac{(5y-6)}{2}= \frac{3y-2+y}{3} \\ \\\frac{(5y-6)}{2}= \frac{(4y-2)}{3} \\ \\3(5y-6)=2(4y-2) \\ \\ 15y-18=8y-4 \\ \\ 15y-8y=-4+18 \\ \\ 7y = 14\to y = \frac{14}{7}\to \boxed{y=2}$

Espero que te sirva, salu2!!!!