Question

ayuda con este problema

Answer 1

ctg Ф= cos37

ctgФ= 4/5 tg= 5/4

√41

sen =

(cscФ²-1) tgФ

(√41/5)²-1) 5/4

41/25  -1 )5/4

(41-25/25)× 5/4

16/25×5/4

20/25 = 0,8

5

(sec37 + tg37)/(sec53 + tg53)

(5/4+ 3/4)/(5/3+4/3)

8/4÷9/3

8×3/9×4

24/36

2/3

6)

(sen²45+ tg²60)   (sec60 4 tg37)

((1/√2)²+ √3²)   (2+4(3/4))

1/2+3)(2+3)

7/2×5

35/2

17,5