Question

Resuelve: (1/√28 + √(4/7)) * 14/5 * √(4/14) ..... Por favor necesito ahorita.

Answer 1

$( \frac{1}{ \sqrt{28} }+ \sqrt{ \frac{4}{7} })* \frac{14}{5}* \sqrt{ \frac{4}{14} } = \\ \\ ( \frac{1}{ \sqrt{7*4} }+ \frac{2}{ \sqrt{7} })* \frac{14}{5}* \frac{2}{ \sqrt{14} }= \\ \\ ( \frac{1}{2 \sqrt{7} }+ \frac{2}{ \sqrt{7} })* \frac{14}{5}* \frac{2}{ \sqrt{14} } = \\ \\ \frac{1+4}{2 \sqrt{7} }* \frac{14}{5}* \frac{2}{ \sqrt{14} }= \\ \\ \frac{5}{2 \sqrt{7} }* \frac{14}{5}* \frac{2}{ \sqrt{14} }= \\ \\ \frac{5*14*2}{2 \sqrt{7} *5* \sqrt{14} }=$

$\frac{14*2}{2 \sqrt{7}* \sqrt{14} }= \\ \\ \frac{28}{2 \sqrt{7*14} }= \\ \\ \frac{28}{2 \sqrt{98} }* \frac{ \sqrt{98} }{ \sqrt{98} }= \frac{28 \sqrt{98} }{2*98}= \frac{14 \sqrt{98} }{98}$


$\frac{7 \sqrt{98} }{49} = \frac{ \sqrt{98} }{7}$

$\frac{ \sqrt{49*2} }{7}= \frac{7 \sqrt{2} }{7}= \sqrt{2}$

Answer 2

Veamos:
(1/√28+√4/7) x 14/5 x √4/14
(1/2√7+2/√7) x 14/5 x 2/√14
5/2√7 x 14/5 x 2/√14
  (5x14x2)
_________
2√7x5x√14

  28
____
2√98


  14     √98
____ x ___
√98     √98

14√98
_____
   98

7√98
____
  49

7x7√2
_____
   49

√2 = respuesta!
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