Question

M= 6sen 90°+2 cos 180°
3sen 0°- csc 270°

Answer 1

Hola!! ☺☺

Recordemos que

* sen 90° = 1
* cos 180° = -1
* sen 0° = 0
* csc 270° = -1

Ahora solo reemplazamos

$M = 3 \sin(90) + 2 \cos(180) \\ \\ M = 3(1) + 2( - 1) = 1$

$N = 3 \sin(0) - \csc(270) \\ \\ N = 3(0) - ( - 1) \\ \\ N = 1$