Respuestas
Cuantos gramos de Al2O3 y H2O se necesitan para obtener 350 gramos de Al(OH)3
Al2O3 + 3 H2O → 2 Al(OH)3
Mm Al2O3 = 101,96 g/mol
H2O = 18 g/mol
Al(OH)3 = 78 g/mol
1. calcular gramos de Al2O3
g Al2O3 = 350 g Al(OH)3 x 1 mol Al(OH)3 x 1 mol Al2O3 x 101.96 g Al2O3
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78 g Al(OH)3 2 mol Al(OH)3 1 mol Al2O3
g Al2O3 = 228.75
2. calcular gramos de agua
g Al2O3 = 350 g Al(OH)3 x 1 mol Al(OH)3 x 3 mol H2O x 18 g H2O
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78 g Al(OH)3 2 mol Al(OH)3 1 mol Al2O3
g H2O = 121.15