Question

tga-tgb =tga x tgb x (cotgb-cotga)

Answer 1

Hola,

Demostrar la siguiente Identidad Trigonométrica:

$\tan(a) - \tan(b) = \tan(a) \times \tan(b) ( \cot(b) - \cot(a) ) \\ \tan(a) - \tan(b) = \tan(a) \times \tan(b) \times \cot(b) - \tan(a) \times \tan(b) \times \cot(a) \\ \tan(a) - \tan(b) = \tan(a) \times \tan(b) \times \frac{1}{ \tan(b) } - \tan(a) \times \tan(b) \times \frac{1}{ \tan(a) } \\\tan(a) - \tan(b) = \frac{\tan(a) \times \tan(b) }{ \tan(b) } - \frac{\tan(a) \times \tan(b) }{ \tan(a) } \\ \tan(a) - \tan(b) = \tan(a) - \tan(b)$
Espero que te sirva, Saludos.