Respuestas
8.15 aplicar ley general de lo gases
V1 P1 / T1 = V2 P2 / T2
V1 = 1.00 L V2 = 4.00 L
T1 = 25 + 273 = 298 K T2 = 200 + 273 = 473 K
P1 = 1.25 atm P2 = ¿?
calcular P2 = ¿?
P2 = ( 1.00 L x 1.25 atm x 473 K ) / (4.00 L x 298 K)
P2 = 0.496 atm.
8.16
Aplicar la ley de los gases ideales
P x V = n x R x T
R = 0.0821 (L atm / mol K)
a)
P = 1.00 atm V = (n x R x T) / P
V = ¿?
n = 1.00 mol
T = 273 K
V = (n x R x T) / P
V = ( 1.00 mol x 0.0821 (L atm / mol K) x 273 K) / 1.00 atm
V = 22.41 atm
b)
P = 0.500 atm V = (n x R x T) / P
V = ¿?
n = 1.00 mol
T = 0 ºC + 273 = 273 K
V = (n x R x T) / P
V = ( 1.00 mol x 0.0821 (L atm / mol K) x 273 K) / 0.500 atm
V = 44.82 atm
c)
P = 5 atm n = (P x V) / ( R x T)
V = 10.0 L
n = ¿?
T = 110 ºC + 273 = 373 K
n = ( 5.00 atm x 10.0 L) / ( 0.0821 (L atm / mol K) x 373 K)
n = 1.632 moles
d)
P = 0.452 atm T = (P x V) / ( R x n)
V = 5 mL / 1000 = 0.005 L
n = 0.001 MOL
T = ¿?
T = ( 0.452 atm x 0.005 L) / ( 0.0821 (L atm / mol K) x 0.001 mol)
T = 27.52 K
e)
P = ¿? P = (n x R x T) / V
V = 5.00 L
n = 1.25 mol
T = 330 ºC + 273 = 573 K
P = (n x R x T) / V
P = ( 1.25 mol x 0.0821 (L atm / mol K) x 573 K) / 5 L
P = 11.76 atm