Question

lim┬(x→-1)⁡= (x^2+3x+2)/(x^2-1)

Answer 1

$\displaystyle \lim_{x\to-1}\frac{x^2+3x+2}{x^2-1}=\lim_{x\to-1}\frac{(x+1)(x+2)}{(x+1)(x-1)}=\lim_{x\to-1}\frac{x+2}{x-1}=\frac{-1+2}{-1-1}=-\frac{1}{2}$