Respuestas
₊₅ ₋₂ ₊₇ ₋₂
Mn⁺² + (BiO3)⁻¹ + (H)⁺¹ → (MnO4)⁻¹ + (Bi)⁺³
(Mn)⁺² → (MnO4)⁻¹
(BiO3)⁻¹ → (Bi)⁺³
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(Mn)⁺² + 4H2O → (MnO4)⁻¹ + 8(H⁺) + 5⁻e Ι 2
2e⁻ + 6(H⁺) + (BiO3)⁻¹ → (Bi)⁺³ +3H2O Ι 5
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2(Mn)⁺² + 8H2O → 2(MnO4)⁻¹ + 16(H⁺) + 10e⁻ sumar las
10e⁻ + 30(H⁺) + 5(BiO3)⁻¹ → 5(Bi)⁺³ + 15H2O semirreacciones
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2(Mn)⁺²+8H2O +10e⁻+30(H⁺)+5(BiO3)⁻¹→2(MnO4)⁻¹+16(H⁺) + 10e⁻+5(Bi)⁺³+ 15H2O
igualar las semirreacciones
2(Mn)⁺² + 5(BiO3)⁻¹ + 14(H⁺) → 5(Bi)⁺³+ 7H2O (balanceada)