RESOLVER ELIMINANDO LOS SIGNOS

La primera

(3x6)/2+(10/5)x3

La segunda

(8x5)+(4-3)x2+(6/3)

La tercera

(9+6-3)/4+[(8-2)/3-(5-3)/2]

La cuarta

[(6+2)/(11-7)]+[5/(6-1)]

La quinta

(5x4x3)/(15-3)+18/(11-5)3

La sexta

9[15/(6-1)-(9-3)/2]

La septima

(9+3)5-[2/(3-2)]+[8x6/4]-2+5(9-2)

Respuestas

Respuesta dada por: pcantugarcia
0

La primera

(3x6)/2+(10/5)x3  = 18/2 + 2x3 = 9 + 6 = 15

La segunda

(8x5)+(4-3)x2+(6/3)  =40 + 1x2 + 2 = 40 + 2 + 2= 44

La tercera

(9+6-3)/4+[(8-2)/3-(5-3)/2] =  12/4 + [6/3 - 2/2] = 3 + [2- 1] = 3 + 1 = 4

La cuarta

[(6+2)/(11-7)]+[5/(6-1)]  =[8/4] + [5/5] = 2 + 1 = 3

La quinta

(5x4x3)/(15-3)+18/(11-5)3  = (60/12) + (18/6x3) = 5 + (18/18) = 5 + 1 = 6

La sexta

9[15/(6-1)-(9-3)/2]=  9[15/5 - 6/2] =9[3-3] = 9[0] = 0

La séptima

(9+3)5-[2/(3-2)]+[8x6/4]-2+5(9-2)  = (11)5 - [2/1] + [48/4] -2 +5(7) =

= 55 - 2 + 12 -2 +35 = 98

Saludos,

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