Respuestas
7.
Sumar todas las resistencias.
a) En serie
R = R1 + R2 +R3
R = 10 + 5 + 15
R = 30Ω
Ley de Ohm
I = V / R
I = 6V / 30Ω
I = 0,2A
b) En paralelo
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/10 + 1/5 + 1/15
1/R = 3+6+2/30
1/R = 11/30
R = 30/11
R = 2,73Ω
Ley de Ohm
I = V / R
I = 5V / 2,73Ω
I = 1,83A
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8.
Sumar: R2 R3 y R4 (serie)
Rb = R2 + R3 +R4
Rb = 4 + 6 + 8
Rb = 18Ω
Sumar: Rb R5 (paralelo)
Ra = Rb*R5 / Rb+R5
Ra = 18*5 / 18+5
Ra = 3,91Ω
Resistencia total
Sumar: R1 Ra R6 (serie)
R = R1 + Ra + R6
R = 3 + 3,91 + 7
R = 13,91Ω
Ley de Ohm
I = V / R
I = 12V / 13,91Ω
I = 0,86A
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9.
b)Sumar en paralelo
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/2 + 1/4 + 1/8
1/R = 4+2+1 / 8
1/R = 7/8
R = 8/7
R = 1,14Ω
Ley de Ohm
V = I.R
V = 4A * 1,14Ω
V = 4,57v
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10.
Sumar: R1 R2 (paralelo)
R = R1*R2 / R1+R2
R = 12*4 / 12+4
R = 3Ω
Ley de Ohm
I = V / R
I = 6V / 3Ω
I = 2A