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Utilizaremos el Teorema de Pitágoras para determinar la longitud de cada lado
a.
![{30}^{2} = {5}^{2} + {x}^{2} \\ \\ 900 = 25 + {x}^{2} \\ \\ {x}^{2} = 875 \\ \\ x = \sqrt{875} \\ \\ x \approx 29.58 {30}^{2} = {5}^{2} + {x}^{2} \\ \\ 900 = 25 + {x}^{2} \\ \\ {x}^{2} = 875 \\ \\ x = \sqrt{875} \\ \\ x \approx 29.58](https://tex.z-dn.net/?f=+%7B30%7D%5E%7B2%7D++%3D++%7B5%7D%5E%7B2%7D++%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C+900+%3D+25+%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C++%7Bx%7D%5E%7B2%7D++%3D+875+%5C%5C++%5C%5C+x+%3D++%5Csqrt%7B875%7D++%5C%5C++%5C%5C+x++%5Capprox+29.58)
b.
![{17}^{2} = {15}^{2} + {x}^{2} \\ \\ 289 = 225 + {x}^{2} \\ \\ {x}^{2} = 64\\ \\ x = \sqrt{64} \\ \\ x = 8 {17}^{2} = {15}^{2} + {x}^{2} \\ \\ 289 = 225 + {x}^{2} \\ \\ {x}^{2} = 64\\ \\ x = \sqrt{64} \\ \\ x = 8](https://tex.z-dn.net/?f=+%7B17%7D%5E%7B2%7D++%3D++%7B15%7D%5E%7B2%7D++%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C+289+%3D+225+%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C++%7Bx%7D%5E%7B2%7D++%3D+64%5C%5C++%5C%5C+x+%3D++%5Csqrt%7B64%7D++%5C%5C++%5C%5C+x++%3D+8)
c.
![{10}^{2} = {6}^{2} + {x}^{2} \\ \\ 100 =64+ {x}^{2} \\ \\ {x}^{2} = 36\\ \\ x = \sqrt{36} \\ \\ x = 6 {10}^{2} = {6}^{2} + {x}^{2} \\ \\ 100 =64+ {x}^{2} \\ \\ {x}^{2} = 36\\ \\ x = \sqrt{36} \\ \\ x = 6](https://tex.z-dn.net/?f=%7B10%7D%5E%7B2%7D++%3D++%7B6%7D%5E%7B2%7D++%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C+100+%3D64%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C++%7Bx%7D%5E%7B2%7D++%3D+36%5C%5C++%5C%5C+x+%3D++%5Csqrt%7B36%7D++%5C%5C++%5C%5C+x++%3D+6)
d.
![{25}^{2} = {24}^{2} + {x}^{2} \\ \\ 625 = 576+ {x}^{2} \\ \\ {x}^{2} = 49\\ \\ x = \sqrt{49} \\ \\ x = 7 {25}^{2} = {24}^{2} + {x}^{2} \\ \\ 625 = 576+ {x}^{2} \\ \\ {x}^{2} = 49\\ \\ x = \sqrt{49} \\ \\ x = 7](https://tex.z-dn.net/?f=%7B25%7D%5E%7B2%7D++%3D++%7B24%7D%5E%7B2%7D++%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C+625+%3D+576%2B++%7Bx%7D%5E%7B2%7D++%5C%5C++%5C%5C++%7Bx%7D%5E%7B2%7D++%3D+49%5C%5C++%5C%5C+x+%3D++%5Csqrt%7B49%7D++%5C%5C++%5C%5C+x++%3D+7)
Utilizaremos el Teorema de Pitágoras para determinar la longitud de cada lado
a.
b.
c.
d.
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